Respuesta :

Answer:

y = [tex]\frac{5}{2}[/tex] x - 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = [tex]\frac{5}{2}[/tex] , thus

y = [tex]\frac{5}{2}[/tex] x + c ← is the partial equation

To find c substitute (2, 0) into the partial equation

0 = 5 + c ⇒ c = 0 - 5

y = [tex]\frac{5}{2}[/tex] x - 5 ← equation of line

The equation of the line is the way of represent the line by the given point in the coordinate plane and the its slope.. Thus the equation of the line with point (2,0) and slope 5/2 is,

[tex]y=\dfrac{5}{2} x-2[/tex]

Given information;

The point of the line through which the line passes are (2,0).

The slope of the line is 5/2.

Equation of the line

The equation of the line is the way of represent the line by the given point in the coordinate plane and the its slope.

The standard form of the equation of the line for point and slope can be given as,

[tex](y-y_1)=m(x-x_1)[/tex]

Put the values,

[tex](y-0)=\dfrac{5}{2} (x-2)[/tex]

Solve it further;

[tex]y=\dfrac{5}{2} x-2[/tex]

Thus the equation of the line with point (2,0) and slope 5/2 is,

[tex]y=\dfrac{5}{2} x-2[/tex]

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