What is the equation of the line that passes through the point (−3,4) and has a slope of 1 ?

Answer:
y = x + 7
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = 1, thus
y = x + c ← is the partial equation
To find c substitute (- 3, 4) into the partial equation
4 = - 3 + c ⇒ c = 4 + 3 = 7
y = x + 7 ← equation of line
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We have following equation to find the point-slope form of the linear functions.
[tex]y - y(0) = m \times ( \: x - x(0) \:) [/tex]
In which :
[tex]y(0) = y \: \: given \: \: point = 4[/tex]
[tex]x(0) = x \: \: given \: \: point = - 3[/tex]
[tex]m = slope = 1[/tex]
Now just need to put the coordinates and the slope in the above equation.
[tex]y - 4 = 1 \times ( \: x - ( - 3) \: )[/tex]
[tex]y - 4 = x + 3[/tex]
Add sides 4
[tex]y - 4 + 4 = x + 3 + 4[/tex]
[tex]y = x + 7[/tex]
Done...
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