A sample survey was taken of 100 students to determine which of three homecoming themes students prefer. The percentages of students
selecting themes A and B are shown in the table.
Theme A (96)
Theme B (%)
25
45
If the remaining students selected theme C, which statistical model could be used to make predictions about the theme a random student might
prefer?
O A 5 white marbles, 6 yellow marbles, and 9 green marbles
OB. 5 white marbles, 6 yellow marbles, and 8 green marbles
OC 4 white marbles, 6 yellow marbles, and 9 green marbles
OD 4 white marbles, 6 yellow marbles, and 8 green marbles

A sample survey was taken of 100 students to determine which of three homecoming themes students prefer The percentages of students selecting themes A and B are class=

Respuesta :

Following the same proportions as the table, the correct option is:

A. 5 white marbles, 6 yellow marbles and 11 green marbles.

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From the table, we have that:

  • 25% of the students prefer Theme A(white).
  • 45% of the students prefer Theme B(green).
  • The rest, that is, 100 - (25 + 45) = 100 - 70 = 30% of the students prefer Theme C(yellow).

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For the marbles, we have to find an option in which the proportions are the same, that is: 25% white, 45% green, 30% yellow.

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Option A:

Out of 20, 5 white, 6 yellow and 11 green.

[tex]\frac{5}{20} = 0.25, \frac{6}{20} = 0.3, \frac{11}{20} = 0.55[/tex]

Same proportions, thus, option A is correct.

A. 5 white marbles, 6 yellow marbles and 11 green marbles.

A similar question is given at https://brainly.com/question/19905617

Answer:

A.  5 white marbles, 6 yellow marbles, and 9 green marbles

Step-by-step explanation:

the amount of marbles adds up to 20, this would make one marble worth 5/100. so 5 white marbles is 25% (theme A) 9 green marbles is 45% (theme B) and 6 yellow marbles is 30% (theme C)

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