Answer:
[tex]{ \boxed{ \bold{ \sf{Acceleration \: ( \: a) = 8 \: m/ {s \: }^{2} }}}}[/tex]
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♨ Question :
- A car starts from rest and is moving at 60.0 m/s after 7.50 s. What is the car's average acceleration ?
♨ [tex] \underbrace{ \sf{Required \: Answer : }}[/tex]
☄ Given :
- Initial velocity ( u ) = 0
- Final velocity ( v ) = 60.0 m/s
- Time ( t ) = 7.50 s
☄ To find :
✒ We know ,
[tex] \boxed{ \underline{ \bold{ \sf{Acceleration \: ( \: a) = \frac{Final velocity ( v ) - Initial velocity ( u)}{t} }}}}[/tex]
Substitute the values and solve for a.
➛ [tex] \sf{a = \frac{60.0 - 0}{7.50}} [/tex]
➛ [tex] \sf{a = \frac{60.0}{7.50}} [/tex]
➛ [tex] \boxed{ \boxed{ \sf{a = 8 \: m/ {s \: }^{2} }}}[/tex]
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✑ Additional Info :
- When a certain object comes in motion from rest , in the case , initial velocity ( u ) = 0
- When a moving object comes in rest , in the case , final velocity ( v ) = 0
- If the object is moving with uniform velocity , in the case , u = v.
- If any object is thrown vertically upwards in the case , a = -g
- When an object is falling from certain height , in the case , final velocity at maximum height ( v ) = 0.
Hope I helped!
Have a wonderful time ツ
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