Answer:
The slope that is perpendicular to the line will be:
[tex]m_2=+\frac{1}{2}[/tex]
Step-by-step explanation:
Given the equation
[tex]2x\:+\:y\:=\:6\:[/tex]
We know that
[tex]y=mx+b[/tex] is the slope-intercept form of a line where m is the slope and b is the y-intercept.
So, writing the equation in the slope-intercept form
[tex]2x\:+\:y\:=\:6\:[/tex]
[tex]\:y=-2x+6[/tex]
here
[tex]m=-2[/tex] ∵ [tex]y=mx+b[/tex]
As we know that for perpendicular lines, one slope is the negative reciprocal of the other.
Therefore, the slope that is perpendicular to the line will be:
[tex]m_2=+\frac{1}{2}[/tex]
