Answer:
The cat's speed when it slid off the table was 2.53 m/s
Explanation:
Horizontal Motion
When an object is thrown horizontally at a speed v, from a height h, it describes a curved path ruled by gravity, until it hits the ground.
the range or maximum horizontal distance traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
The situation described in the problem fits into the concept of a horizontal launch when the cat slides off the table and gets to the ground some distance ahead.
It's given the range as d=1.3m and the height h=1.3 m, thus we can find the cat's speed by solving the equation for v:
[tex]\displaystyle v=d\cdot\sqrt{\frac {g}{2h}}[/tex]
Where [tex]g=9.81\ m/s^2[/tex]
Substituting values:
[tex]\displaystyle v=1.3\cdot\sqrt{\frac {9.81}{2\cdot 1.3}}[/tex]
[tex]\displaystyle v=1.3\cdot\sqrt{\frac {9.81}{2.6}}[/tex]
Calculating:
v = 2.53 m/s
The cat's speed when it slid off the table was 2.53 m/s
