DOG is a right triangle formed by the placement of 3 squares, what is the area of the shaded square?

Answer:
289 in^2
Step-by-step explanation:
1. Find side of the small square: (DG=a)
64= a^2
a= 8
2. Find hypotenuse of triangle being formed: (OG=c and DO=b)
[tex]a^{2}[/tex] + [tex]b^{2}[/tex] = [tex]c^{2}[/tex]
[tex]8^{2}[/tex] + [tex]15^{2}[/tex] = [tex]c^{2}[/tex]
c= 17
3. Find area of square:
[tex]c^{2}[/tex]= A
(17)*(17)= 289 in^2
The area of the shaded square when the DOG is a right triangle formed by the placement of 3 squares so it should be 289 [tex]in^2[/tex].
Find we have to determine the side of the small square i.e. (DG=a)
Now
64= [tex]a^2[/tex]
So,
a= 8
Now find the hypothenuse
[tex]8^2 + 15^2 = c^2[/tex]
c = 17
Now the area should be like
= (17) (17)
= 289 [tex]in^2[/tex].
Hence, The area of the shaded square when the DOG is a right triangle formed by the placement of 3 squares so it should be 289 [tex]in^2[/tex].
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