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The number of fungi in a petri dish on the first day was 87 cells. If the number of fungi increase at a rate of 62% per day, how many bacteria cells will there be after 7 days?

Respuesta :

Answer:

There will be 2,547 bacteria after 7 days.

Step-by-step explanation:

[tex]87*1.62^{7} =2547[/tex]

After 7 days there will be 2547.55 cells in a petri dish if the number of fungi in a petri dish on the first day was 87 cells. If the number of fungi increases at a rate of 62% per day.

What is an exponential function?

It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent y = a×

where a is a constant and a>1

We have:

The number of fungi in a petri dish on the first day was 87 cells. If the number of fungi increases at a rate of 62% per day.

As we know,

The standard form of the exponential growth equation:

y = a(1 + r)×

Here,

a is the starting value:

a = 87 cells

r = 62% = 0.62

x = 7 days

y = 87(1 + 0.62)⁷

After solving:

y = 2547.55 cells

Thus, after 7 days there will be 2547.55 cells in a petri dish if the number of fungi in a petri dish on the first day was 87 cells. If the number of fungi increases at a rate of 62% per day.

Learn more about the exponential function here:

brainly.com/question/11487261

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