Answer:
P = 981000 [Pa] or 98.1 [kPa]
Explanation:
To calculate the pressure at that depth we can use the following expression that defines the static pressure of a fluid as a function of the density and depth of the body with respect to the surface of the liquid.
[tex]P=Ro*g*h[/tex]
where:
P = pressure [Pa]
Ro = density of the water = 1000 [kg/m³]
g = gravity acceleration = 9.81 [m/s²]
h = depth = 100 [m]
[tex]P = 1000*9.81*100\\P = 981000 [Pa][/tex]
