Hey There!
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Answer:
[tex]\huge\boxed{Theta=25.67}[/tex]
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DATA:
Range = R = 78m
Initial Velocity = [tex]V_i[/tex] = 30m/s
Angle(theta) = ?
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SOLUTION:
The Range is given by,
[tex]R =\frac{V_0^2}{g}Sin2(theta)\\\\78 = \frac{30^2}{10}Sin2(theta)\\\\Sin2(theta) = \frac{780}{900}\\\\Sin2(theta) = \frac{13}{15}\\\\Sin(theta) = \frac{13}{30}\\\\theta = Sin^{-1}\frac{13}{30}\\\\theta = 25.67^0[/tex]
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Best Regards,
'Borz'
