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Determine the total impedance, phase angle, and rms current in an LRC circuit connected to a 10.0 kHz , 809 V (rms) source if L = 22.3 mH , R = 8.16 kΩ , and C = 5750 pF .

Respuesta :

Answer:

Impedance = 8,274.02Ω

Phase angle = 170.48°

rms current = 0.0978A

Explanation:

The impedance of the LRC circuit is expressed as;

[tex]Z = \sqrt{R^2+(X_L-X_C)^2} \\[/tex]

R is the resistance

XL is the inductive reactance = 2πfL

XC is the capacitive reactance = 1/2πfC

f is the frequency

L is the inductance

C is the capacitance

Given

L = 22.3 mH  = 0.0223H

R = 8.16 kΩ = 8160Ω

C = 5750 pF = 5750 * 10^-12

Get XL;

XL = 2πfL

XL= 2π(10*10^3)(0.0223)

XL = 2(3.14)(223)

XL = 1400.44Ω

Get XC;

XC = 1/2πfC

XC = 1/2(3.14)(10,000)(5750 * 10^-12)

XC = 1/0.0003611

XC = 2,769.32Ω

Get the impedance;

[tex]Z = \sqrt{R^2+(X_L-X_C)^2} \\Z = \sqrt{(8160)^2+(1400.44-2769.32)^2} \\Z = \sqrt{(8160)^2+(-1,368.87)^2} \\Z = \sqrt{66,585,600+1,873,821.44} \\Z = \sqrt{68,459,421.44} \\Z = 8,274.02 ohms\\[/tex]

Get the phase angle;

[tex]\theta = tan^{-1}\frac{XL-XC}{R}\\\theta = tan^{-1}\frac{-1368.87}{8160}\\\theta = tan^{-1}(-0.1677)\\\theta = -9.52^0\\\theta = 180-9.52\\\theta = 170.48^0[/tex]

Get the rms current

I = V/Z

I = 809/8274.02

I = 0.0978A