Answer:
The appropriate response will be "Length must be increased by 0.012%".
Explanation:
The given values is:
ΔT = 5 s/day
Now,
⇒ [tex]\frac{\Delta T}{T} =\frac{5}{24\times 60\times 60}[/tex]
On multiplying both sides by "100", we get
⇒ [tex]\frac{\Delta T}{T}\times 100 =\frac{500}{24\times 60\times 60}[/tex]
⇒ [tex]\frac{\Delta T}{T}\times 100=0.005787[/tex] (%)
∵ [tex]T=2\pi\sqrt{\frac{l}{g} }[/tex]
On substituting the values, we get
⇒ [tex]\frac{\Delta T}{T}[/tex]% = [tex]\frac{1}{2}\times \frac{\Delta l}{l}[/tex]%
On applying cross multiplication, we get
⇒ [tex]\frac{\Delta l}{l}[/tex]% = [tex]2\times \frac{\Delta T}{T}[/tex]%
⇒ = [tex]2\times 0.05787[/tex]
⇒ = [tex]0.011574[/tex]
⇒ = [tex]0.012[/tex]%
