Select one of the factors of x2y3 − 11x2y + 6y2 − 66

we try to factor by maybe grouping
experiment

(x²y³-11x²y)+(6y²-66)
factor
x²y(y²-11)+6(y²-11)
undistribute (y²-11) from each
(x²y+6)(y²-11)
we can force a factor out of the 2nd group in the form of a difference of 2 perfect squares
(x²y+6)(y-√11)(y+√11)
either of those 3 are factors

Answer Link

okpalawalter8 okpalawalter8 · Answer 2 · 2021-10-19T10:50:34+02:00

We have that for the Question "Select one of the factors of x2y3 − 11x2y + 6y2 − 66" it can be said that

The three factors are

[tex](x^2y+6)[/tex]
[tex](y\sqrt{y-11})[/tex]
[tex](y+\sqrt{11})[/tex]

From the question we are told

Select one of the factors of x2y3 − 11x2y + 6y2 − 66

Generally The factors of an expression are variable, constants and expression s that maForke up the main expression

Therefore

x2y3 − 11x2y + 6y2 − 66

We have

[tex]x^2y(y^2-11)+6(y^2-11)\\\\x^2y+6*(y^2-11)\\\\Therefore\\\\x^2y+6*(y\sqrt{y-11})*(y+\sqrt{11})[/tex]

Hence The three factors are

[tex](x^2y+6)[/tex]
[tex](y\sqrt{y-11})[/tex]
[tex](y+\sqrt{11})[/tex]

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