Light enters a transparent material from air at 30.0° to the normal. It continues within the material at the angle of refraction of 23.0°. What is the critical angle for total internal reflection when this material is surrounded by air?

Respuesta :

Answer:

The value is [tex]c = 51.38 ^o[/tex]

Explanation:

From the question we are told that

    The angle of incidence is  [tex]\theta_i = 30^o[/tex]

    The angle of refraction is  [tex]\theta_r = 23^o[/tex]

     

Generally at the point where the light enters the material ,  from Snell's law  we have that

          [tex]n = \frac{sin (\theta_i)}{sin (\theta_{r})}[/tex]

Here  n is the refractive index of the material

=>       [tex]n = \frac{sin (30)}{sin (23)}[/tex]  

=>       [tex]n = 1.28[/tex]  

Generally for total internal  reflection , the critical angel is evaluated using Snell law as follows

          [tex]n = \frac{sin (90)}{sin (c)}[/tex]

=>       [tex]1.28 * sin (c) = sin(90)[/tex]  

=>      [tex]c = sin^{-1} [0.7813 ][/tex]

=>    [tex]c = 51.38 ^o[/tex]