Answer:
The value is [tex]\Delta P = 40082 \ Pa[/tex]
Explanation:
From the question we are told that
The length of the bottom of the barge below the water line when loaded is [tex]d_2 = 4.09 \ m[/tex]
The length of the bottom of the barge below the water line when empty is [tex]d_1 = 1.80 \ m[/tex]
Generally the difference in pressure is mathematically represented as
[tex]\Delta P = \rho * g * d_2[/tex]
Here [tex]\rho[/tex] is the density of water with value [tex]\rho = 1000 \ kg/m^3[/tex]
[tex]\Delta P = 1000 * 9.8 * ( 4.09 )[/tex]
=> [tex]\Delta P = 40082 \ Pa[/tex]
