By the remainder theorem, the value 2 is a root of P(x) because P(2) = 0
What are the roots of a function?
The roots of a function are the zeros of the function
The equation of the function is given as:
[tex]P(x)= \sqrt{2-x}[/tex]
Calculate P(2) and P(-2)
[tex]P(2)= \sqrt{2-2} = 0[/tex]
[tex]P(-2)= \sqrt{2-(-2)} = 2[/tex]
Since P(2) = 0, then the value 2 is a root of P(x)
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