contestada

Consider the following balanced equation:
P4(s) + 6F2(e)
4PF3(g)
If 1.25 moles of P4(s) is reacted with 6 moles of F2(g), How many moles of PF3(e) are
produced?
O 5 moles
4 moles
O 6 moles
O 3 moles

Consider the following balanced equation P4s 6F2e 4PF3g If 125 moles of P4s is reacted with 6 moles of F2g How many moles of PF3e are produced O 5 moles 4 moles class=

Respuesta :

ardni313

Moles of PF₃ : 4

Further explanation

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

[tex]\tt P_4(s)+6F_2(g)\rightarrow 4PF_3(g)[/tex]

1.25 moles of P₄(s) is reacted with 6 moles of F₂(g)

Limiting reactant : the smallest ratio (mol divide by coefficient)

P₄ : F₂ =

[tex]\tt \dfrac{1.25}{1}\div \dfrac{6}{6}=1.25\div 1\rightarrow F_2~limiting~reactant(smallest~ratio)[/tex]

mol PF₃ based on mol of limiting reactant(F₂), so mol PF₃ :

[tex]\tt \dfrac{4}{6}\times 6~moles=4~moles[/tex]

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