Hello!
a)
Use the kinematic equation to solve for the acceleration:
[tex]v_{f} = v_{i} + at[/tex]
In this instance, the final velocity is 0 because he comes to a stop. We can solve for the acceleration by plugging in the given values:
0 = 33 + (12)a
0 = 33 + 12a
-33 = 12a
-33 / 12 = a --> a = -2.75 m/s²
b) Find the amount of distance necessary to stop. Use the formula:
[tex]v_{f} ^{2} = v_{i} ^{2} + 2ad[/tex]
Plug in the values:
0² = 33² + 2(-2.75 · d)
0 = 1089 - 5.5d
-1089 = -5.5d
d = 198 meters. Therefore, the squirrel would survive.
c)
Find the velocity at 100 meters by using the same formula as before:
[tex]v_{f} ^{2} = v_{i} ^{2} + 2ad[/tex]
However, in this instance, we are solving for the final velocity. Plug in the given points to solve:
vf² = 33² + 2(-2.75 · 100)
vf² = 1089 + (-550)
vf² = 539
vf = √539
vf ≈ 23.22 m/s.
