Answer:
[tex]8.115\ \text{g}[/tex]
Step-by-step explanation:
The decay model or the mass remaining after [tex]t[/tex] years have passed is
[tex]A(t)=16e^{-0.00012t}[/tex]
Now
[tex]t[/tex] = Time taken in years = [tex]5657\ \text{years}[/tex]
[tex]A(5657)=16e^{-0.00012\times 5657}[/tex]
[tex]\Rightarrow A(5657)=8.115\ \text{g}[/tex]
Carbon present after 5657 years is [tex]8.115\ \text{g}[/tex].