Answer:
Step-by-step explanation:
[tex]\frac{3x^{2}-2}{3x-2}-\frac{x}{2-3x}=\frac{3x^{2}-2}{3x-2}-\frac{x}{-(3x-2)}\\\\=\frac{3x^{2}-2}{3x-2}-\frac{-x}{3x-2}\\\\=\frac{3x^{2}-2}{3x-2}+\frac{x}{3x-2}\\\\=\frac{3x^{2}-2+x}{3x-2}\\\\=\frac{(3x-2)(x+1)}{3x-2}\\\\=x+1[/tex]1)
1) I took negative sign from (2-3x)
2) I multiplied the to successive negative sign.
3) 3x² +x - 2 = 3x² + 3x - 2x - 2*1
= 3x( x + 1) - 2(x + 1)
= (x + 1)(3x-2)
4) I stroked out (3x-2) which was common in denominator and numerator
