Find the Area of the figure below, composed of a square and four semicircles.
Rounded to the nearest tenths place

Answer:
The area of figure is: 2313
Step-by-step explanation:
We need to find area of the figure.
Figure is composed of one square and 4 semicircles.
So, we find area of both square and semicircles.
First we will find area of square.
Length of square = 30
The formula used is: [tex]Area\:of\:square=Length\times Length[/tex]
Putting values and finding area of square
[tex]Area\:of\:square=Length\times Length\\Area\:of\:square=30\times 30\\Area\:of\:square=900[/tex]
Now, we will find the area of semicircle
Diameter of semicircle = 30
Radius r = d/2 = 30/2 = 15
Now, The formula used is: [tex]Area\:of\:semicircle=\frac{\pi r^2}{2}[/tex]
Putting values and finding area of semicircle
[tex]Area\:of\:semicircle=\frac{\pi r^2}{2}\\Area\:of\:semicircle=\frac{3.14\times (15)^2}{2}\\Area\:of\:semicircle=353.25[/tex]
Now, we have 4 semicircles, all will have same area as their diameter is 30
So, [tex]The\: area\: of\: 4\: semicircle = 4*353.25 = 1413[/tex]
So, the area of the figure will be:
Area of figure= Area of Square+ Area of 4 semicircles
Area of figure = 900+1413
Area of figure=2313
So, the area of figure is: 2313