Answer:
The quarterback applies a force of 8.08 N to the ball during the pass.
Explanation:
To find the force we need to calculate the acceleration first so we can use the following equation:
[tex] F = ma [/tex]
Now, we can calculate the acceleration as follows:
[tex] x_{f} = x_{0} + v_{0}t + \frac{1}{2}at^{2} [/tex]
Since the ball starts from rest [tex]v_{0} = 0[/tex] and [tex]x_{0} = 0[/tex]:
[tex] a = \frac{2*x_{f}}{t^{2}} = \frac{2*1.909 m}{(0.439 s)^{2}} = 19.81 m/s^{2} [/tex]
Now we can find the force:
[tex] F = 0.408 kg*19.81 m/s^{2} = 8.08 N [/tex]
Therefore, the quarterback applies a force of 8.08 N to the ball during the pass.
I hope it helps you!
