Answer:
1.1 × 10⁵ J
Explanation:
Step 1: Given data
- Mass of the aluminum block (m): 1000.0 g
- Initial temperature: 70 °C
- Final temperature: 192.4 °C
- Specific heat for aluminum (c): 0.89 J/g.°C
Step 2: Calculate the change in the temperature
ΔT = 192.4 °C - 70 °C = 122 °C
Step 3: Calculate the heat required (Q)
We will use the following expression.
Q = c × m × ΔT
Q = 0.89 J/g.°C × 1000.0 g × 122 °C
Q = 1.1 × 10⁵ J
