chandani123 chandani123

09-01-2021
Physics

contestada

a)
F E
60. The temperature of source and sink of cannot engine are 400K
and 300K respectively. What is its efficiency?
h) 75%
c) 33.3% d) 25%

Respuesta :

topeadeniran2 topeadeniran2

14-01-2021

Answer: 25%

Explanation:

From the question, we are informed that the temperature of source and sink of cannot engine are 400K

and 300K respectively.

The efficiency will be calculated as:

= 1 - t/T

= 1 - 300/400

= 1 - 3/4

= 1/4

= 25%

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