Answer:
E_total = 0
Explanation:
In this exercise we are asked for the electric field created by two charges at the midpoint between them, since the electric field is a vector magnitude it must be added as vectors. The equation that describes the electric field for a charge is
[tex]E = k \frac{q}{r^{2} }[/tex]
in this case the two charges are positive, therefore the field is salient, in the adjoint we can see a diagram of the system
E_total = E₁ -E₂
we calculate the electric field of charge 1 with q = + 5 10⁻³ C and a distance r = L / 2 = 100/2 = 50 m
E₁ = [tex]\frac{9 10^{9} \ 5 10^{-3} }{ 50^{2} }[/tex]
E₁ = 1.8 10⁴ N / C
the magnitude of the electric field of charge 2 is equal, but the sense is opposite.
Since the two charges have the same sign, the addition of vectors gives zero
E_total = 0
if the charges were of different signs, the fields would be added
E_total = 3.6 10⁴ N / A
