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Heights of American adult women are normally distributed with mean 63.6 inches and standard deviation 2.5 inches. Find the height of an adult woman that corresponds to the 80th percentile.

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Answer:

65.7

Step-by-step explanation:

Given ;

Mean, m = 63.6

Standard deviation, s = 2.5

80th percentile = 80 / 100 = 0.8

The Zscore corresponding to the 80th percentile ; Z < P = 0.842 (Z probability calculator)

Zscore = (x - m) / s

0.842 = (x - 63.6) / 2.5

0.842 * 2.5 = x - 63.6

2.105 = x - 63.6

x = 63.6 + 2.105

x = 65.705

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