The mass of nitrogen monoxide produced from 2.5 grams of oxygen is 1.875 grams
4NH₃ + 50₂ → 4NO + 6H₂0
The limiting reagent is 0₂ because the least moles of this are used in the reaction.
Therefore, it will determine the amount of product formed.
From the chemical reaction above
10(16) g of 0₂ gives (4×14 + 4×16) g of NO
2.50 g of 0₂ will give ? of NO
cross multiply
mass of NO formed = 2.50 × 120 / 160
mass of NO formed = 300 / 160
mass of NO formed = 1.875 grams
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