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Five times a number plus four times a second number is 20. Four times
the first number added by two times the second number is 16. Write the
system of equations for this situation. *

Respuesta :

clarch19

Answer:

first number is 4

second number is 0

Step-by-step explanation:

y = 1st number

x = 2nd number

system of equations:

5y + 4x = 20

4y + 2x = 16

I multiplied the second equation by -2 to eliminate the 'x-values'

-2(4y + 2x = 16)  =                 -8y - 4x = -32

now add to 1st equation:     5y + 4x = 20

                                              -3y = -12

y = 4

solve for 'x':

5(4) + 4x = 20

20 + 4x = 20

4x = 0

x = 0

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