Answer:
The radius of the curve is 9,183.67 m.
Explanation:
Given;
velocity of the jet plane, v = 600 m/s
acceleration of the jet plane, a = 4g = 4 x 9.8 m/s² = 39.2 m/s²
The radius of the curve is calculated from centripetal acceleration formula as given below;
[tex]a = \frac{v^2}{r} \\\\r = \frac{v^2}{a} \\\\r = \frac{600^2}{39.2} \\\\r = 9,183.67 \ m[/tex]
Therefore, the radius of the curve is 9,183.67 m.
