Respuesta :
Answer : Electric field, E = 50 N/C
Explanation :
It is given that,
Charge, q = +0.08 C
The force exerted by the electric field, F = 4 N
The electric field is defined as the ratio of electric force and electric charge.
Mathematically, it can be written as :
[tex]E=\dfrac{F}{q}[/tex]
[tex]E=\dfrac{4\ N}{0.08\ C}[/tex]
[tex]E=50\ N/C[/tex]
The magnitude of electric field is 50 N/C.
We know that the direction of electric force and the electric field are in same direction.
So, the direction of electric field is same as electric charge i.e. in right direction.
