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A rectangular room measures 12 feet by 15 feet. The entire room is to be covered with rectangular titles that measure 3 inches by 2 inches. If the tiles are sold at 10 for 1.20 what will be the cost to tile the room?

Respuesta :

bartdrinksmalk
Each tile is 3 in. × 2 in. = [tex]\frac{1}{4}[/tex] ft × [tex]\frac{1}{6}[/tex] ft
The area of a tile is [tex]\frac{1}{4}*\frac{1}{6}=\frac{1}{24}[/tex] ft²

The area of the room is 12*15=180 ft²

The number of tiles is 180÷[tex]\frac{1}{24}[/tex]=180*24=4320

which is 432 sets of 10 tiles.

The total cost is $1.20/set * 432 sets = $518.40
varshamittal029

Cost of the tile to the room will be ₹518.40

What is area of the rectangle?

  • Length of the rectangle be l
  • Breadth of the rectangular be b
  • Area of the rectangle is given by A = l × b sq.units

We know that 1 ft = 12 inch

12 ft = 12*12 = 144 inch

15 ft = 15*12 = 180 inch

Dimension of the rectangular room = 12ft by 15ft = 144in × 180in

Area of the rectangle = length × breadth

The area of the room in sq.inch is given by 144*180 = 25920 sq. in

The area of one tile is 3inches *2inches = 6 sq.in

The total number of tiles required is 25920/6 = 4320 tiles

cost of 10 tiles = $1.20

To find cost of 4320 tiles

cost of 4320 tiles = (4320 × 1.20)/10

= ₹518.40

Hence, Cost of the tile to the room will be ₹518.40

Learn more about Area of rectangle here:

https://brainly.com/question/25292087

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