Answer:
The correct answer is "21195 N".
Explanation:
The given values are:
Tensile strength,
= 3000 MN/m²
Diameter,
= 3.0 mm
i.e.,
= 3×10⁻³ m
Now,
The maximum load will be:
= [tex]Tensile \ strength\times Area[/tex]
On substituting the values, we get
= [tex](3000\times 10^6)(\frac{\pi}{4} (3\times 10^{-3})^2)[/tex]
= [tex](3000\times 10^6)(\frac{3.14}{4} (3\times 10^{-3})^2)[/tex]
= [tex]21195 \ N[/tex]
