Finding angle measures between intersecting lines. Note: Angles necessarily drawn to scale. x=__

Answer:
x=25+30=55 since the vertically opposite angle are equal.sorry the no is not clear in question
Answer:
[tex]\boxed{\tt x= 45^{\circ}}[/tex]
Step-by-step explanation:
∠BEG and ∠DEB combine to form ⇒ ∠DEG, which is a vertical angle with ∠x because it's the opposite from ∠x.
(Vertical angles are always congruent, or of equal measure)
So, [tex]\tt \angle BEG +\angle DEB=\angle x[/tex]
[tex]\tt \angle BEG +\angle DEB=\angle x[/tex]
[tex]\tt 25^{\circ}+20=x[/tex]
[tex]\tt 45^{\circ}=x[/tex]
[tex]\tt x= 45^{\circ}[/tex]
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