Answer:
Step-by-step explanation:
Given quadratic equation is,
y = -2x² + 4x + 5
y = -2(x² - 2x) + 5
y = -2(x² - 2x + 1 - 1) + 5
y = -2(x² - 2x + 1) + 2 + 5
y = -2(x - 1)² + 7
This equation is in the vertex form of the quadratic equation,
y = a(x - h)² + k
where, (h, k) is the vertex of the parabola.
Therefore, vertex of the given quadratic equation is (1, 7)
The equation can be rewritten as y = -2(x - 1)² + 7.
Therefore, the vertex of the graph of the function y = -2x² + 4x + 5 in the xy-coordinate plane is located at the point (1, 7).
