Idea63
contestada

The equation Negative one-half(x + 1) = (y – 5)2 is represented by which graph?

its Not A or B

Respuesta :

Answer:

Step-by-step explanation:

one-half(x + 1) = (y – 5)^2, written symbolically, is (1/2)(x - [-1]) = (y - 5)^2

or x + 1 = 2(y - 5)^2 (after multiplying all terms by 2).   Because the y term is squared, we know immediately that the graph is a horizontal (not vertical) parabola.  

This equation (immediately above) can be written as

x = 2(y - 5)^2 - 1

The standard equation of a horizontal parabola with vertex (h, k) is x = c(y - k)^2 + h.  Comparing this to the given quadratic:  

we see that k = 5 and h = -1.  This tells us that the vertex of this graph is (-1, 5), and that the graph is stretched horizontally because c = 2 is greater than 1.

To graph this, it's best to make a short table of points, as follows, remembering that y is the independent value and x depends on y through the equation given above.

 y    x = 2(y - 5)^2 - 1    (x, y)

 0    x = 49                    (49, 0)

 2    x = 2(-3)^2 - 1         (17, 2)

  1   x = 2(-4)^2 - 1          (31,  1)

  vertex (already found) (-1, 5)

The graph of equation 1/2(x+1)=[tex](y-5)^{2}[/tex] looks like graph of a horizontal parabola.

What is equation?

Equation is relationship between two or more variables that are expressed in equal to form. Equation of two variables look like ax+by=c. It is of many types like linear equation, quadratic equation, cubic equation, etc.

How to graph equation?

one-half(x + 1) = (y – 5)^2, written symbolically, is (1/2)(x - [-1]) = [tex](y-5)^{2}[/tex]

or x + 1 = 2[tex](y-5)^{2}[/tex]. Because the y term is squared, we know immediately that the graph is a horizontal (not vertical) parabola.  

This equation can be written as

x = 2[tex](y-5)^{2}[/tex] - 1

The standard equation of a horizontal parabola with vertex (h, k) is

x = c[tex](c-k)^{2}[/tex] + h.  Comparing this to the given quadratic:  

we see that k = 5 and h = -1.  This tells us that the vertex of this graph is (-1, 5), and that the graph is stretched horizontally because c = 2 is greater than 1.

To graph this, it's best to make a short table of points, as follows, remembering that y is the independent value and x depends on y through the equation given above.

y    x = 2[tex](y-5)^{2}[/tex] - 1    (x, y)

0    x = 49                    (49, 0)

2    x = 2(-3)^2 - 1         (17, 2)

 1   x = 2(-4)^2 - 1          (31,  1)

 vertex (already found) (-1, 5)

Learn more about equation at https://brainly.com/question/2972832

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