Find all solutions of the equation in the interval [0, 2)

Answer:
x = [tex]\frac{\pi }{3}[/tex] , [tex]\frac{2\pi }{3}[/tex] , [tex]\frac{4\pi }{3}[/tex] , [tex]\frac{5\pi }{3}[/tex]
Step-by-step explanation:
sin²x = 3cos²x
[tex]\frac{sin^2 x}{cos^2 x}[/tex] = 3
tan²x = 3, x ∈ [0, 2π)
tan x = √3 , x ∈ [0, 2π)
x = [tex]\frac{\pi }{3}[/tex] , [tex]\frac{2\pi }{3}[/tex] , [tex]\frac{4\pi }{3}[/tex] , [tex]\frac{5\pi }{3}[/tex]