Answer:
x = [tex]-\frac{45}{15}[/tex]
Step-by-step explanation:
We have the equation: 3 + [tex]\frac{3}{4} x[/tex] = [tex]\frac{7}{10}[/tex]
Move the constant (in this case the constant is 3) to the right side of the equation, changing its sign
[tex]\frac{3}{4} x[/tex] = [tex]\frac{7}{10}[/tex] - 3
Calculate the difference.
[tex]\frac{3}{4} x[/tex] = [tex]-\frac{23}{10}[/tex]
Divide.
(when dividing two fractions, you can change it to a multiplication problem by switching the numerator and denominator of the divisor.)
So, we get the equation [tex]-\frac{23}{10}[/tex] x [tex]\frac{4}{3}[/tex] which is [tex]-\frac{45}{15}[/tex] .
I hope this helps!
