Answer:
The probability of the given scenario occuring is about 0.0153.
Step-by-step explanation:
A standard deck contains 52 cards.
We want the first card to be a spade. In a standard deck, 13 out of the total 52 cards are spades.
So, the probability that the first card is a spade is 13/52 or simply 1/4.
Now, we will draw a second card without replacing the first card. Since we did not replace the first card, the total amount of cards in the deck is now 51.
This time, we want a heart. 13 cards of the remaining 51 will be hearts. So, the probability that the second card is a heart is 13/51.
Now that we've drawn two cards without replacing them, the total number of cards left is 50.
And since we've drawn (or would like to have drawn) a heart as our second card, the total number of cards that are hearts is now 12.
Then the probability of the third card being hearts will be 12/50 or 6/25.
Then the probability that our first card is a spades, second card is a heart, and the third and final card is also a heart without any replacements will be:
[tex]\displaystyle P(\text{spade, heart, heart})=\frac{1}{4}\cdot \frac{13}{51}\cdot \frac{6}{25}=\frac{13}{850}\approx0.0153[/tex]
The probability of the given scenario occuring is about 0.0153.
