Answer: [tex]32.65\ m[/tex]
Explanation:
Given
mass of laptop m=2 kg
The velocity of car u=8 m/s
The coefficient of static friction is [tex]\mu_s=0.4[/tex]
The coefficient of kinetic friction is [tex]\mu_k=0.2[/tex]
As the car is moving, so the coefficient of kinetic friction comes into play
deceleration offered by friction [tex]\mu_kg=0.2\times 9.8\ m/s^2[/tex]
Using the equation of motion [tex]v^2-u^2=2as\\[/tex]
insert the values
[tex]0^2-8^2=2(-0.2\times 9.8)s\\\\s=\dfrac{64}{1.96}\\\\s=32.65\ m[/tex]
