Respuesta :
Answer:
True
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
As the normal distribution is symmetric, we have that [tex]P(z < -A) = P(z > A)[/tex]
For example:
[tex]z = -2[/tex] has a pvalue of 0.0228, which means that [tex]P(z < -2) = 0.0228[/tex]
[tex]z = 2[/tex] has a pvalue of 0.9772, which means that [tex]P(z > 2) = 1 - 0.9772 = 0.0228[/tex]
True or False?
As shown above, this statement is True, due to the symmetry of the normal distribution.
