Answer and Step-by-step explanation:
Use the distance formula to solve for sides that are sloped/diagonal. The points I am using are the from the points of the shape.
1.
Lengths:
DE = 3
EF = 3
GF = 4
DG = [tex]distance = \sqrt{(1-2)^2 + (-2-1)^2} = \sqrt{1+9} = \sqrt{10}[/tex]
3 + 3 + 4 + [tex]\sqrt{10}[/tex] = 13.16 units
2.
Lengths:
LK = 4
JL = [tex]\sqrt{(-2-0)^2 + (-4-(-2))^2} = \sqrt{4+4} = \sqrt{8}[/tex]
JK = [tex]\sqrt{(2-0)^2 + (-4-(-2))^2} = \sqrt{4+4} = \sqrt{8}[/tex]
[tex]\sqrt{8} +\sqrt{8} +4 =[/tex] 9.66 units
3.
Lengths:
MN = 2
MQ = [tex]\sqrt{(-4 - (-3))^2 +(-2-1)^2 } = \sqrt{1 + 9} = \sqrt{10}[/tex]
QP = 4
NP = [tex]\sqrt{(0 - (-1))^2 + (-2 - 1)^2} = \sqrt{1 + 9} = \sqrt{10}[/tex]
[tex]\sqrt{10} +\sqrt{10} + 2 + 4 =[/tex] 12.32 units
4.
Lengths:
TY = 5
YX = 4
TX = [tex]\sqrt{(7-3)^2+(-2-3)^2} = \sqrt{16 + 25} = \sqrt{41}[/tex]
[tex]\sqrt{41} + 4 + 5 =[/tex] 15.4 units
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