laabsm102 laabsm102

10-05-2021
Mathematics

contestada

Find the roots of the polynomial equation. x^2+2x−48=0
−8, 6
−6, 8
−12, −4
−4, 12

Respuesta :

minion77 minion77

10-05-2021

(x+8)(x-6)= 0
x^2-48+8x-6x=0
x^2-48+2x=0
x+8=0 x-6=0
x= -8 x=6
The answer is -8 and 6, I did the process in case you need it

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