Law of cosines: a2 = b2 + c2 – 2bccos(A)

Which equation correctly uses the law of cosines to solve for y?
92 = y2 + 192 – 2(y)(19)cos(41°)
y2 = 92 + 192 – 2(y)(19)cos(41°)
92 = y2 + 192 – 2(9)(19)cos(41°)
y2 = 92 + 192 – 2(9)(19)cos(41°)

Law of cosines a2 b2 c2 2bccosA Which equation correctly uses the law of cosines to solve for y 92 y2 192 2y19cos41 y2 92 192 2y19cos41 92 y2 192 2919cos41 y2 9 class=

Respuesta :

In this case,
a = y
b = 9
c = 19
So...
[tex]a^2 = b^2 + c^2 - 2bc*\cos(A)[/tex]
[tex]y^2 = 9^2 + 19^2 - 2*9*19*\cos(41^{\circ})[/tex]
which means the answer is choice D

The correct answer is:

D. [tex]y^{2}=9^{2}+19^{2}-2(9)(19)cos(41)[/tex]

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