Answer:
The simplified form of the given expression [tex]\dfrac{\frac{2}{5t}-\frac{3}{3t} }{\frac{1}{2t}+\frac{1}{2t}}=-\frac{3}{5}[/tex]
Step-by-step explanation:
Given expression [tex]\dfrac{\frac{2}{5t}-\frac{3}{3t} }{\frac{1}{2t}+\frac{1}{2t} }[/tex]
We have to simplify the given expression [tex]\dfrac{\frac{2}{5t}-\frac{3}{3t} }{\frac{1}{2t}+\frac{1}{2t} }[/tex]
Consider the given expression [tex]\dfrac{\frac{2}{5t}-\frac{3}{3t} }{\frac{1}{2t}+\frac{1}{2t} }[/tex]
Consider denominator [tex]\frac{1}{2t}+\frac{1}{2t}[/tex]
Apply rule, [tex]\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}[/tex]
[tex]=\frac{1+1}{2t}=\frac{1}{t}[/tex]
Now, apply fraction rule, [tex]\frac{a}{\frac{b}{c}}=\frac{a\cdot \:c}{b}[/tex]
We get,
[tex]=\frac{\left(\frac{2}{5t}-\frac{3}{3t}\right)t}{1}[/tex]
Simplify, we get,
[tex]\frac{t\left(\frac{2}{5t}-\frac{1}{t}\right)}{1}[/tex]
Simplify, we get,
[tex]\frac{t\left(\frac{2}{5t}-\frac{1}{t}\right)}{1}[/tex]
Further simplify by [tex]\frac{-a}{b}=-\frac{a}{b} \ and\ a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}[/tex]
We get, [tex]=-\frac{3t}{5t}[/tex]
Thus, [tex]-\frac{3}{5}[/tex]
