Answer:
Explanation:
The equation you need for this is a one-dimensional:
[tex]v_f^2=v_0^2 +2a[/tex]Δx (sorry that looks weird. It is all one equation, even though it's "crooked"!)
We have final velocity, acceleration, and the displacement, and we are looking for initial velocity. I see after working this out that you don't use the die-hard rules for significant digits, so I adapted to get an answer that matches exactly what one of your choices is. Filling in:
[tex](13.5)^2=v_0^2+2(.50)(49.3)[/tex] and
[tex](13.5)^2-2(1.50)(49.3)=v_0^2[/tex] and
[tex]\sqrt{(13.5)^2-2(1.50)(49.3)}=v_0[/tex] so
v₀ = 5.86 m/s
