Answer:
[tex](f-g)(x)=-4x^2+10x[/tex]
Step-by-step explanation:
We are given the two functions:
[tex]f(x)=-x^2+6x-1\text{ and } g(x)=3x^2-4x-1[/tex]
And we want to find:
[tex](f-g)(x)[/tex]
This is equivalent to:
[tex]=f(x)-g(x)[/tex]
Substitute:
[tex]=(-x^2+6x-1)-(3x^2-4x-1)[/tex]
Distribute:
[tex]=-x^2+6x-1+(-3x^2+4x+1)[/tex]
Rearrange:
[tex]=(-x^2-3x^2)+(6x+4x)+(-1+1)[/tex]
Combine like terms. Hence:
[tex](f-g)(x)=-4x^2+10x[/tex]
