Try this option:
1. the required surface area consists of: A=A₁+A₂+A₃, where
2. A₁=pi*r*l - the surface of the cone:
pi=3.14; r=4/2=2 cm; l=sqrt(6²+2²)=2√10≈6.33 (cm);
A₁=3.14*2*6.33=39.74 (cm²).
3. A₂=a²-pi*r² - the surface of the top plane:
A₂=36-3.14*4=23.43 (cm²).
4. A₃=5*a² - the surface of the five planes of the given cube:
A₃=5*6²=180 (cm²).
5. the required area:
A=39.74+23.43+180=243.17 (cm²).
Answer: 243.17
