Answer:
f(x) = (-1/2)(x^2 + 8x - 15)
Step-by-step explanation:
This function has two roots: -3 and 5. Most likely it is a quadratic (all of which have two roots).
Then f(x) = a(x + 3)(x - 5)
The graph goes through (1. 8): Therefore, y = 8 when x = 1:
f(1) = a(1 + 3)(1 - 5) = 8, or
a(4)(-4) = 8, or
-16a = 8, which leads to a = -1/2.
Thus the quadratic in question is f(x) = (-1/2)(x + 3)(x - 5), or
f(x) = (-1/2)(x^2 + 8x - 15)
The function is a quadratic function given by f(x) = (-1/2)(x + 3)(x - 5) and f(x) = (-1/2)(x² + 8x - 15).
A function is a law that relates a dependent and an independent variable.
The function has x-intercepts at (-3,0) and (5,0),
The function has two roots: -3 and 5
So, the equation is a quadratic equation represented by
f(x) = a(x + 3)(x - 5)
The function goes through the point (1. 8)
y = 8 when x = 1
f(1) = a(1 + 3)(1 - 5) = 8
-16a = 8,
a = (-1/2)
f(x) = (-1/2)(x + 3)(x - 5)
f(x) = (-1/2)(x² + 8x - 15)
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