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Suppose that the width of a certain rectangle is 1 inch more than one-fourth of its length. The perimeter of the rectangle is 72 inches. Find the length and width of the rectangle.

Respuesta :

sreedevi102

Answer:

Length = 28 inches

Width =  8 inches

Step-by-step explanation:

Let length be L

Let Width be W

Given : W = 1 + (1/4)L

Perimeter = 2 x ( L + W)

[tex]72 = 2 (L + (1 + \frac{1}{4} L))\\\\36 = L + 1 + \frac{1}{4} L\\\\36 - 1 = \frac{5}{4} L\\\\35 = \frac{5}{4} L\\\\5L = 35 \times 4\\\\L = \frac{140}{5} = 28 \ in[/tex]

[tex]W = 1 + (\frac{1}{4} \times 28) = 1 + 7 = 8 \ in[/tex]

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