Answer:
I'll setup the problem and you can do the calculations
Step-by-step explanation:
a.
[tex]V = \pi( {D}^{2} \div 4)H[/tex]
V = volume; D = diameter; H = height of can
b.
Area of the Tin is the total area of the 2 Tin circles
one circle's area A is
[tex]A = \pi {D}^{2} \div 4[/tex]
A = area; D = diameter
calculate A
Then multiply by 2
c.
The area of the cardboard is the circumstance of the circle
times the height
[tex]SA = \pi DH[/tex]
d.
add answers from b and c
